Compile a conservation planning problem into an mixed integer linear programming problem.

## Usage

```
compile(x, ...)
# S3 method for ConservationProblem
compile(x, compressed_formulation = NA, ...)
```

## Arguments

- x
`problem()`

object.- ...
not used.

- compressed_formulation
`logical`

should the conservation problem compiled into a compressed version of a planning problem? If`TRUE`

then the problem is expressed using the compressed formulation. If`FALSE`

then the problem is expressed using the expanded formulation. If`NA`

, then the compressed is used unless one of the constraints requires the expanded formulation. This argument defaults to`NA`

.

## Value

A `optimization_problem()`

object.

## Details

This function might be useful for those interested in understanding
how their conservation planning `problem()`

is expressed
as a mathematical problem. However, if the problem just needs to
be solved, then the `solve()`

function should just be used.

**Please note that in nearly all cases, the default argument to
compressed_formulation should be used**. The only situation where
manually
setting the argument to

`formulation`

is desirable is during testing.
Manually setting the argument to `formulation`

will at best
have no effect on the problem. At worst, it may result in
an error, a misspecified problem, or unnecessarily long
solve times.## Examples

```
# \dontrun{
# load data
sim_pu_raster <- get_sim_pu_raster()
sim_features <- get_sim_features()
# build minimal conservation problem
p <-
problem(sim_pu_raster, sim_features) %>%
add_min_set_objective() %>%
add_relative_targets(0.1)
# compile the conservation problem into an optimization problem
o <- compile(p)
# print the optimization problem
print(o)
#> An optimization problem (<OptimizationProblem>)
#> • model sense: min
#> • dimensions: 5, 90, 450 (rows, columns, cells)
#> • variables: 90 (B)
# }
```